Me too. I think it's a masterpiece.Originally Posted by glamourama
Me too. I think it's a masterpiece.
230
LII-Ne
"Come to think of it, there are already a million monkeys on a million typewriters, and the Usenet is NOTHING like Shakespeare!"
- Blair Houghton
Johari
lol you cheated.
that is, if that's even right.
On the contrary, I figured it out carefully and compared notes with another LII.
LII-Ne
"Come to think of it, there are already a million monkeys on a million typewriters, and the Usenet is NOTHING like Shakespeare!"
- Blair Houghton
Johari
do you know where the problem is from?
I googled it, and found a site that listed it among other problems. I don't know whether that was your source.
LII-Ne
"Come to think of it, there are already a million monkeys on a million typewriters, and the Usenet is NOTHING like Shakespeare!"
- Blair Houghton
Johari
Yo, Brill. ::
And this, too, shall pass away.
ILI
plagiarism! niffweed bering damned! haha jk no but our little common room does suck. i discussed this in a provocative thread entitled "What's the dilly yo?" in an attempt to bring this problem to the forefront. We should try to make an effort to make this a cool place for gammas!
ESFp-Fi sub
6w7 sx/so/sp
it came from an AIME (american invitational mathematics examination) from a couple years ago
Yep, that site I found was an AIME archive...
Hi, Flame!
m has to be an integer that can be multiplied by both 5 and 7 to make them divisible by the length of the cube's sides. Since 5 and 7 are prime, that number has to be 12 (the length of the cube's sides).
I would help, but a mass of Alpha nonsense is probably the one thing you don't need...
LII-Ne
"Come to think of it, there are already a million monkeys on a million typewriters, and the Usenet is NOTHING like Shakespeare!"
- Blair Houghton
Johari
Brill, what are you talking about? Bore them all to death with Ti, i don't care.
And this, too, shall pass away.
ILI
But true gammas don't need cool places. That's where your great idea collapses.
Despite the fact we're supposed to be the territorial ones?
And this, too, shall pass away.
ILI
I like warm places personally. Unless it's hot outside, then cool places are nicer. But this is Winter, so..
ILI (Indescribable Lovemaking Inc.)
5w4 so/sx
"IP temperament! Because today's concerns are tomorrow's indifferences!"
Lord Fnorgle's Domain - A slowly growing collection of music, poetry and literature.
Stickam music performances
true- places become cool just by us being there haha
ESFp-Fi sub
6w7 sx/so/sp
not just cool but freeeeeezing
awwww shit- take that alphas! hahaha
ESFp-Fi sub
6w7 sx/so/sp
That was funny.
That's one helluva confusing set of sentences you just constructed
PoLR war?I'm a desert man, myself. Favorite temperatures 80-90 Fahrenheit... if it gets down to 70, I'm wearing a jacket.
Now, I may as well solve the more difficult problem of making that problem unsolveable, but still allowing the line to hit edges of the cube. The naive answer is to change the 5 or the 7 to Pi, thus making the light only hit four vertices. And in fact, that is the only answer, because in order to hit an edge, two elements of the vector...
Ah, I'd better explain the vector. The light beam's direction is [12,5,7] - the distance the line travels in each direction.
...must be multiplied by the same number X (rational or irrational) to become divisible by 12. Any such number X can be converted to any other such number X by multiplication by a rational number. Thus, given any such number for one pair of edges X and any such number for the other pair of edges Y, both X and Y will be divisible by the same real number Z, and multiplying the vector by the value X*Y/Z will cause it to reach a vertex. Thus, if the light ray cannot reach a vertex, it cannot reach more than four edges of the cube (proof by contradiction).
There. Some of you might be able to decipher that with some effort.
I'm tired of making sense. Given a cactus farm in Minnesota guarded by a horde of rabid beagles, how would you go about rescuing a mule trapped in said cactus farm?
Yes, go ahead and rip me to shreds, it will give you a sense of unity.
LII-Ne
"Come to think of it, there are already a million monkeys on a million typewriters, and the Usenet is NOTHING like Shakespeare!"
- Blair Houghton
Johari
go back to ur people ure making the gammas not as coolPoLR war?
Now, I may as well solve the more difficult problem of making that problem unsolveable, but still allowing the line to hit edges of the cube. The naive answer is to change the 5 or the 7 to Pi, thus making the light only hit four vertices. And in fact, that is the only answer, because in order to hit an edge, two elements of the vector...
Ah, I'd better explain the vector. The light beam's direction is [12,5,7] - the distance the line travels in each direction.
...must be multiplied by the same number X (rational or irrational) to become divisible by 12. Any such number X can be converted to any other such number X by multiplication by a rational number. Thus, given any such number for one pair of edges X and any such number for the other pair of edges Y, both X and Y will be divisible by the same real number Z, and multiplying the vector by the value X*Y/Z will cause it to reach a vertex. Thus, if the light ray cannot reach a vertex, it cannot reach more than four edges of the cube (proof by contradiction).
There. Some of you might be able to decipher that with some effort.
I'm tired of making sense. Given a cactus farm in Minnesota guarded by a horde of rabid beagles, how would you go about rescuing a mule trapped in said cactus farm?
Yes, go ahead and rip me to shreds, it will give you a sense of unity.
ESFp-Fi sub
6w7 sx/so/sp
Yes, go ahead and rip me to shreds, it will give you a sense of unity.
there are no cheeseburgers in finland.
I don't understand - how does this take reflections into account?Now, I may as well solve the more difficult problem of making that problem unsolveable, but still allowing the line to hit edges of the cube. The naive answer is to change the 5 or the 7 to Pi, thus making the light only hit four vertices. And in fact, that is the only answer, because in order to hit an edge, two elements of the vector...
Ah, I'd better explain the vector. The light beam's direction is [12,5,7] - the distance the line travels in each direction.
...must be multiplied by the same number X (rational or irrational) to become divisible by 12. Any such number X can be converted to any other such number X by multiplication by a rational number. Thus, given any such number for one pair of edges X and any such number for the other pair of edges Y, both X and Y will be divisible by the same real number Z, and multiplying the vector by the value X*Y/Z will cause it to reach a vertex. Thus, if the light ray cannot reach a vertex, it cannot reach more than four edges of the cube (proof by contradiction).
There. Some of you might be able to decipher that with some effort.
Here's how I think of it: instead of reflecting the line, reflect the cube infinitely through space. When the light bounces off a side of the cube, it's basically the same as it going into a new, identical cube. So you can imagine the light going straight, and passing through a bunch of cubes until it hits a vertex.
LII-Ne
"Come to think of it, there are already a million monkeys on a million typewriters, and the Usenet is NOTHING like Shakespeare!"
- Blair Houghton
Johari
Yes there are, they are called juustohampurilainen.
...the human race will disappear. Other races will appear and disappear in turn. The sky will become icy and void, pierced by the feeble light of half-dead stars. Which will also disappear. Everything will disappear. And what human beings do is just as free of sense as the free motion of elementary particles. Good, evil, morality, feelings? Pure 'Victorian fictions'.
INTp
... Maybe I shouldn't have encouraged him...
But hey, he's using Ti.
And this, too, shall pass away.
ILI
Yeah, there's a black market.
lies. its impossible since there are no cheeseburgers in finland.
Go eat.
And this, too, shall pass away.
ILI
Gamma is still the most dead forum - why?
Alpha, Beta, and Delta each all have at least twice as much activity.
Why is this?
Te-INTp/ILI, my wife: Fi-ISFj/ESI, with laser beam death rays for ESTp/SLEs, lol
16 years of bliss in an Activity relationship
What's wrong with being dead?
Gammas are out making money.
LII-Ne with strong EII tendencies, 6w7-9w1-3w4 so/sp/sx, INxP
WL, are you thinking what I'm thinking?
They might not "lol".
Money is a word with 5 letters in it.
You can spell the money and smell the money.
I advice not to lick it though.
...the human race will disappear. Other races will appear and disappear in turn. The sky will become icy and void, pierced by the feeble light of half-dead stars. Which will also disappear. Everything will disappear. And what human beings do is just as free of sense as the free motion of elementary particles. Good, evil, morality, feelings? Pure 'Victorian fictions'.
INTp
Cyclops is bringing Gamma back.
I'm gonna put this quadra back on the map again.
Most of the posts in gamma aren't from real gammas anyway.
LII-Ne with strong EII tendencies, 6w7-9w1-3w4 so/sp/sx, INxP
lol.
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