Just visit my channel
and search in 4-letters mode: For example "ENFP" - you will
Lots of socionists telling us that they can identify type without mistake. Many socionists have its own database and consider that their typing is true.
I tell to anyone: I am not so as most of them. I recognize that I can do mistake. But I also do everything(and also have lots already done!) to minimize it!
The main difference between of my database and database of other socionists are The highest logical redundancy of proof.
So why I considered that my database - are etalon?
I had been completed 2 huge video-analitical projets
Reinins dichotomies: QuesTIM - DeklaTIM
and "Positivists - Negativists"
most of the people, who entered to this base - are the well known socionists with already, and qualitative identified types. They were: Goulenko, Boukalov, Udalova. So that are the best prerequisites for you to trust my research data.
From all these men you may find the characteristics not only from Jung basis - but also from these experimentally confirmed dychotomies.
I had also worked to make these dichotomies more contrast as it possible, seeking for new criteria which can increase the skill level anyone to identify them - so I did everything to make these dichotomies sense which can provide probability of true typing the same or better than Jung Basis dichotomies had been already researched
What does is that mean?
to simplify the calculations - I will make equal all values of probability of true typing, and set them to the 0,85
So we have:
E N T P
P = E-I*N-S*T-F*P-J = 0,522
E N T P Q +
Only after you provide research about sense of new dichotomies, only after you provide research of contrast of new dichotomies which can provide probability of true typing the same or better than Jung Basis only after that - you can consider that you dichotomies, that you own in practice
are equal to the Jung dichotomies.
So. Back to the example:
E N T P Q +
Dichotomies E N T - are connected to dichotomies Q +, So 1 time mistake will do not cause the mistake in total type identification
These variants are 5
1 time mistake in a P - will cause the result: "Type not identified"
2 times mistake:
There are 6C2 = 15 variants of 2 time mistakes
when a 2 time mistakes happening in Basis 4C2 = 6
= They will cause total mistake in typing
when a 2 time mistakes happening: 1 in Basis and 1 in Q or "+" than we will have also a total mistake in typing. These variants are 2*4C1 = 8
The variant of two time mistake in Q and + will cause result: "Type not identified" These variants: 1
Other variants will give us results as "mistake" or "Type not identified". There are 6C3 + 6C4 + 6C5 + 6C6 = 42 variants
To simplify rest logical steps lets consider all these variants as a "mistake"
So. Lest calculate what do we have
Probability without mistake: 0,85^6 = 0,37715
1 mistake: 5*0,85^5*0,1 = 0,22185
Total probability to of true typing = 0,599
Not identified:0,85^5*0,1+ 0,85^4*0,1^2 = 0,0495
mistake = 1 - 0,599 - 0,0495 = 0,3515
Excluding variants "not identified"
Total probability of true typing = 0,599/(1 - 0,0495) = 0,63019
Mistake = 0,36981
Progress is significant!
In general, I own 10 dichotomies on the same level of Quality - but that is the question of further works
Using by calculator Reinin dichotomies which was created by me, calculating the same way - I had been achieved Total probability of true typing about 95%. Practical experiments shown me the same think: usually I'm finding mistake of my typing in every 20th cases.
Also: if you want a calculator - I will send you.
It calls: Calc2008.txt